#Android get file path from uri code
#Android get file path from uri zip

We should be able to get it from the result of AndroidJNI.CallObjectMethod, but I don't now how so just call againДЄndroidJavaObject inputChannel = inputStream.Call('getChannel') ДЄndroidJavaObject outputStream = new AndroidJavaObject('java.io.FileOutputStream', importPath) ДЄndroidJavaObject outputChannel = outputStream.

IntPtr getDataResult = AndroidJNI.CallObjectMethod(intent.GetRawObject(), method_getData, AndroidJNIHelper.CreateJNIArgArray(new object)) IntPtr method_getData = AndroidJNIHelper.GetMethodID(intent.GetRawClass(), 'getData', '()Ljava/lang/Object ') Get the intent data using AndroidJNI.CallObjectMethod so we can check for null Here's the function I've written which copies the whole of any file given with the intent to another location private void ImportFromIntent(string importPath)ДЄndroidJavaClass unityPlayerClass = new AndroidJavaClass('com.unitењ“d.player.UnityPlayer') So found a way to do this without writing a plugin or resorting to reading byte by byte. $$anonymous$$yFileReadingFunction(my$$anonymous$$nownPath)

#Android get file path from uri code

That code would look something like this AndroidJavaClass unityPlayerClass = new AndroidJavaClass('com.unitењ“d.player.UnityPlayer') ДЄndroidJavaObject activityObject = unityPlayerClass.GetStatic('currentActivity') ДЄndroidJavaObject intent = activityObject.Call('getIntent') ДЄndroidJavaObject intentURI = intent.Call('getData') ДЄndroidJavaObject contentResolver = activityObject.Call('getContentResolver') ДЄndroidJavaObject inputStream = contentResolver.Call('openInputStream', intentURI) ДЇile.WriteAllBytes(my$$anonymous$$nownPath, bytes.ToArray()) In the absolute laziest case you could read all the bytes to memory, write them out to a known file location and then read that file as you normally would. By doing that you can read the file byte by byte, or wrap the input reader in something more sophisticated extract strings. What I'm doing is using the URI to read the file as an input stream. After creating your credentials, download the clientsecret.json file from.

#Android get file path from uri zip

How do I pass the uri to the java File class so I can get the proper path to the zip file? Note: Given the security implications of getting the implementation correct. But the constructor for the File class is getting this error: UnityEngine.AndroidJavaException: : no non-static method 'Ljava/io/File. Here is my attempt to convert the uri: AndroidJavaClass UnityPlayer = new AndroidJavaClass('com.unitењ“d.player.UnityPlayer') ДЄndroidJavaObject currentActivity = UnityPlayer.GetStatic('currentActivity') ДЄndroidJavaObject intent = currentActivity.Call('getIntent') ДЄndroidJavaObject data = intent.Call('getData') ДЄndroidJavaObject fileObject = new AndroidJavaObject('java.io.File', data) I have an external app sending me a URI of a.